Answers for "javascript find element"

29

find element in array javascript

const simpleArray = [3, 5, 7, 15];
const objectArray = [{ name: 'John' }, { name: 'Emma' }]

console.log( simpleArray.find(e => e === 7) )
// expected output 7

console.log( simpleArray.find(e => e === 10) )
// expected output undefined

console.log( objectArray.find(e => e.name === 'John') )
// expected output { name: 'John' }
Posted by: Guest on July-06-2020
50

javascript find

const inventory = [
  {name: 'apples', quantity: 2},
  {name: 'cherries', quantity: 8}
  {name: 'bananas', quantity: 0},
  {name: 'cherries', quantity: 5}
  {name: 'cherries', quantity: 15}
  
];

const result = inventory.find( ({ name }) => name === 'cherries' );

console.log(result) // { name: 'cherries', quantity: 5 }
Posted by: Guest on July-11-2020
12

javascript array.find

const array1 = [5, 12, 8, 130, 44];

const found = array1.find(element => element > 10);

console.log(found);
// expected output: 12
Posted by: Guest on June-01-2020
9

array find

const array1 = [5, 12, 8, 130, 44];

const found = array1.find(element => element > 10);

console.log(found);
// expected output: 12
Posted by: Guest on November-20-2020
0

return object list in find js

const inventory = [
  {name: 'apples', quantity: 2},
  {name: 'bananas', quantity: 0},
  {name: 'cherries', quantity: 5}
];

function isCherries(fruit) {
  return fruit.name === 'cherries' && fruit.name === 'bananas';
}

console.log(inventory.find(isCherries));
// { name: 'cherries', quantity: 5 }
Posted by: Guest on January-11-2021
10

js array find

var ages = [3, 10, 18, 20];

function checkAdult(age) {
  return age >= 18;
}
/* find() runs the input function agenst all array components
   till the function returns a value
*/
ages.find(checkAdult);
Posted by: Guest on April-09-2020

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