find element in array javascript
const simpleArray = [3, 5, 7, 15];
const objectArray = [{ name: 'John' }, { name: 'Emma' }]
console.log( simpleArray.find(e => e === 7) )
// expected output 7
console.log( simpleArray.find(e => e === 10) )
// expected output undefined
console.log( objectArray.find(e => e.name === 'John') )
// expected output { name: 'John' }javascript find
const inventory = [
{name: 'apples', quantity: 2},
{name: 'cherries', quantity: 8}
{name: 'bananas', quantity: 0},
{name: 'cherries', quantity: 5}
{name: 'cherries', quantity: 15}
];
const result = inventory.find( ({ name }) => name === 'cherries' );
console.log(result) // { name: 'cherries', quantity: 5 }javascript array.find
const array1 = [5, 12, 8, 130, 44];
const found = array1.find(element => element > 10);
console.log(found);
// expected output: 12array find
const array1 = [5, 12, 8, 130, 44];
const found = array1.find(element => element > 10);
console.log(found);
// expected output: 12js find in array
const inventory = [
{id: 23, quantity: 2},
{id: '24', quantity: 0},
{id: 25, quantity: 5}
];
// Check type and value using ===
const result = inventory.find( ({ id }) => id === 23 );
// Check only value using ==
const result = inventory.find( ({ id }) => id == 24 );js array find
var ages = [3, 10, 18, 20];
function checkAdult(age) {
return age >= 18;
}
/* find() runs the input function agenst all array components
till the function returns a value
*/
ages.find(checkAdult);Copyright © 2021 Codeinu
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