Answers for "find element in array javascript"

25

find element in array javascript

const simpleArray = [3, 5, 7, 15];
const objectArray = [{ name: 'John' }, { name: 'Emma' }]

console.log( simpleArray.find(e => e === 7) )
// expected output 7

console.log( simpleArray.find(e => e === 10) )
// expected output undefined

console.log( objectArray.find(e => e.name === 'John') )
// expected output { name: 'John' }
Posted by: Guest on July-06-2020
39

javascript find

const inventory = [
  {name: 'apples', quantity: 2},
  {name: 'cherries', quantity: 8}
  {name: 'bananas', quantity: 0},
  {name: 'cherries', quantity: 5}
  {name: 'cherries', quantity: 15}
  
];

const result = inventory.find( ({ name }) => name === 'cherries' );

console.log(result) // { name: 'cherries', quantity: 5 }
Posted by: Guest on July-11-2020
8

javascript array.find

const array1 = [5, 12, 8, 130, 44];

const found = array1.find(element => element > 10);

console.log(found);
// expected output: 12
Posted by: Guest on June-01-2020
8

array find

const array1 = [5, 12, 8, 130, 44];

const found = array1.find(element => element > 10);

console.log(found);
// expected output: 12
Posted by: Guest on November-20-2020
0

js find in array

const inventory = [
  {id: 23, quantity: 2},
  {id: '24', quantity: 0},
  {id: 25, quantity: 5}
];
// Check type and value using ===
const result = inventory.find( ({ id }) => id === 23 );
// Check only value using ==
const result = inventory.find( ({ id }) => id == 24 );
Posted by: Guest on September-12-2021
9

js array find

var ages = [3, 10, 18, 20];

function checkAdult(age) {
  return age >= 18;
}
/* find() runs the input function agenst all array components
   till the function returns a value
*/
ages.find(checkAdult);
Posted by: Guest on April-09-2020

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