javascript array unique values
var arr = [55, 44, 65,1,2,3,3,34,5];
var unique = [...new Set(arr)]
//just var unique = new Set(arr) wont be an arrayjavascript array unique values
var arr = [55, 44, 65,1,2,3,3,34,5];
var unique = [...new Set(arr)]
//just var unique = new Set(arr) wont be an arrayhow to find unique elements in array in javascript
let a = ["1", "1", "2", "3", "3", "1"];
let unique = a.filter((item, i, ar) => ar.indexOf(item) === i);
console.log(unique);javascript find unique values in array
// usage example:
var myArray = ['a', 1, 'a', 2, '1'];
var unique = myArray.filter((v, i, a) => a.indexOf(v) === i);
// unique is ['a', 1, 2, '1']get unique array javascript
// one liner solution to get a unique array by object id
[{_id: 10},{_id: 20}, {_id: 20}].filter((item, i, ar) => ar.findIndex(each => each._id === item._id) === i)unique numbers in array
import java.util.ArrayList;
public class UniqueNumbersInArray {
public static void main(String[] args) {
int arr[] = { 4,5,5,4,5,6,5,8,4,7};
ArrayList<Integer> uniqueArr = new ArrayList<Integer>();
for (int i = 0; i < arr.length; i++) {
int k = 0;
if (!uniqueArr.contains(arr[i])){
uniqueArr.add(arr[i]);
k++;
for (int j = i; j < args.length ; j++) {
if (arr[i]==arr[j]){
k++;
}
}
System.out.println(arr[i]);
System.out.println(k);
}
}
}
}Copyright © 2021 Codeinu
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