Answers for "how to write ajax call in javascript"

3

ajax request in javascript

fetch('https://api.covid19api.com/summary')
            .then(response => response.json())
            .then(data => console.log(data))
            .catch(err => {
                console.log(err)
            });
Posted by: Guest on May-19-2021
6

ajax syntax in javascript

var id = empid;

$.ajax({
    type: "POST",
    url: "../Webservices/EmployeeService.asmx/GetEmployeeOrders",
    data: "{empid: " + empid + "}",
    contentType: "application/json; charset=utf-8",
    dataType: "json",
    success: function(result){
        alert(result.d);
        console.log(result);
    }
});
Posted by: Guest on September-30-2020
3

how to make ajax request javascript

//Change the text of a <div> element using an AJAX //request:
//using JQuery


$("button").click(function(){
  $.ajax({url: "demo_test.txt", success: function(result){
    $("#div1").html(result);
  }});
});



//To send a request to a server, we use the open() //and send() methods of the XMLHttpRequest object:
// Javascript


xhttp.open("GET", "ajax_info.txt", true);
xhttp.send();

//example below
<html>
<body>

<h1>The XMLHttpRequest Object</h1>

<button type="button" onclick="loadDoc()">Request data</button>

<p id="demo"></p>


<script>
function loadDoc() {
  var xhttp = new XMLHttpRequest();
  xhttp.onreadystatechange = function() {
    if (this.readyState == 4 && this.status == 200) {
      document.getElementById("demo").innerHTML = this.responseText;
    }
  };
  xhttp.open("GET", "demo_get.asp", true);
  xhttp.send();
}
</script>

</body>
</html>
Posted by: Guest on January-17-2020
7

ajax

With Ajax, web applications can send and retrieve data from a server asynchronously without interfering with the display and behaviour of the existing page.
Posted by: Guest on August-21-2020
0

js functional ajax requests

function checkUserIdExists(userid, callback) {
        return $.ajax({
        url: 'theurl',
        type: 'GET',
        cache: false,
        data: {
           userid: userid
        }
    })
    .done(callback)
    .fail(function(jqXHR, textStatus, errorThrown) {
        // Handle error
    });
}

checkUserIdExists(2, function(data) {
    console.log(data); // Do what you want with the data returned
});
Posted by: Guest on May-28-2020

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