fibonacci javascript
function Fibonacci(num){
var before = 0;
var actual = 1;
var next = 1;
for(let i = 0; i < num; i++){
console.log(next)
before = actual + next;
actual = next
next = before
}
}
Fibonacci(100);
fibonacci javascript
function Fibonacci(num){
var before = 0;
var actual = 1;
var next = 1;
for(let i = 0; i < num; i++){
console.log(next)
before = actual + next;
actual = next
next = before
}
}
Fibonacci(100);
fibonacci javascript
function Fibonacci(valor){
var anterior = 0;
var atual = 1;
var proximo = 1;
for(let i = 0; i < valor; i++){
console.log(proximo)
anterior = atual + proximo;
atual = proximo
proximo = anterior
}
}
Fibonacci(100);
js fibonacci sequence
var i;
var fib = []; // Initialize array!
fib[0] = 0;
fib[1] = 1;
for (i = 2; i <= 10; i++) {
// Next fibonacci number = previous + one before previous
// Translated to JavaScript:
fib[i] = fib[i - 2] + fib[i - 1];
console.log(fib[i]);
}
fibonacci javascript
function fibonacci(num){
var num1=0;
var num2=1;
var sum;
var i=0;
for (i = 0; i < num; i++){
sum=num1+num2;
num1=num2;
num2=sum;
}
return num2;
}
fibonacci sums javascript
// Implement a method that finds the sum of the first n
// fibonacci numbers recursively. Assume n > 0
function fibsSum(n) {
if ( n === 1 ) {
return 1;
}
if (n === 2 ) {
return 2;
}
let sum = fibsSum(n-1) + n;
return sum;
}
js to confirm fibonnaci
function isFibonacci(n) {
var fib,
a = (5 * Math.pow(n, 2) + 4),
b = (5 * Math.pow(n, 2) - 4)
var result = Math.sqrt(a) % 1 == 0,
res = Math.sqrt(b) % 1 == 0;
//fixed this line
if (result || res == true) // checks the given input is fibonacci series
{
fib = Math.round(n * 1.618); // finds the next fibonacci series of given input
console.log("The next Fibonacci number is " + fib);
} else {
console.log(`The given number ${n} is not a fibonacci number`);
}
}
$('#fib').on("keyup change", function() {
isFibonacci(+this.value)
})
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