javascript array unique values
var arr = [55, 44, 65,1,2,3,3,34,5];
var unique = [...new Set(arr)]
//just var unique = new Set(arr) wont be an arrayjavascript array unique values
var arr = [55, 44, 65,1,2,3,3,34,5];
var unique = [...new Set(arr)]
//just var unique = new Set(arr) wont be an arrayhow to find unique elements in array in javascript
let a = ["1", "1", "2", "3", "3", "1"];
let unique = a.filter((item, i, ar) => ar.indexOf(item) === i);
console.log(unique);array unique values javascript
const myArray = ['a', 1, 'a', 2, '1'];
const unique = [...new Set(myArray)]; // ['a', 1, 2, '1']javascript get unique values from array
const myArray = [1,2,3,1,5,8,1,2,9,4];
const unique = [...new Set(myArray)]; // [1, 2, 3, 5, 8, 9, 4]
const myString = ["a","b","c","a","d","b"];
const uniqueString = [...new Set(myString)]; //["a", "b", "c", "d"]unique values in array javascript
let uniqueItems = [...new Set(items)]unique numbers in array
import java.util.ArrayList;
public class UniqueNumbersInArray {
public static void main(String[] args) {
int arr[] = { 4,5,5,4,5,6,5,8,4,7};
ArrayList<Integer> uniqueArr = new ArrayList<Integer>();
for (int i = 0; i < arr.length; i++) {
int k = 0;
if (!uniqueArr.contains(arr[i])){
uniqueArr.add(arr[i]);
k++;
for (int j = i; j < args.length ; j++) {
if (arr[i]==arr[j]){
k++;
}
}
System.out.println(arr[i]);
System.out.println(k);
}
}
}
}Copyright © 2021 Codeinu
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