Answers for "jquery ajax data"

23

jquery ajax post example

var formData = {name:"John", surname:"Doe", age:"31"}; //Array 

$.ajax({
    url : "https://example.com/rest/getData", // Url of backend (can be python, php, etc..)
    type: "POST", // data type (can be get, post, put, delete)
    data : formData, // data in json format
  	async : false, // enable or disable async (optional, but suggested as false if you need to populate data afterwards)
    success: function(response, textStatus, jqXHR) {
    	console.log(response);
    },
    error: function (jqXHR, textStatus, errorThrown) {
		console.log(jqXHR);
      	console.log(textStatus);
      	console.log(errorThrown);
    }
});
Posted by: Guest on March-10-2020
15

jquery ajax

$.ajax({

   url     : "file.php",
   method  : "POST",

       data: { 
         //key                      :   value 
         action                   	:   action , 
         key_1   					:   value_key_1,
         key_2   					:   value_key_2
       }
   })

   .fail(function() { return false; })
	// Appel OK
   .done(function(data) {

   console.log(data);

 });
Posted by: Guest on May-05-2020
1

jquery ajax request

// Using the core $.ajax() method
$.ajax({
 
    // The URL for the request
    url: "post.php",
 
    // The data to send (will be converted to a query string)
    data: {
        id: 123
    },
 
    // Whether this is a POST or GET request
    type: "GET",
 
    // The type of data we expect back
    dataType : "json",
})
  // Code to run if the request succeeds (is done);
  // The response is passed to the function
  .done(function( json ) {
     $( "<h1>" ).text( json.title ).appendTo( "body" );
     $( "<div class=\"content\">").html( json.html ).appendTo( "body" );
  })
  // Code to run if the request fails; the raw request and
  // status codes are passed to the function
  .fail(function( xhr, status, errorThrown ) {
    alert( "Sorry, there was a problem!" );
    console.log( "Error: " + errorThrown );
    console.log( "Status: " + status );
    console.dir( xhr );
  })
  // Code to run regardless of success or failure;
  .always(function( xhr, status ) {
    alert( "The request is complete!" );
  });
Posted by: Guest on September-21-2021

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