Answers for "jquery ajax form data"

jquery ajax form submission

$(function() {
  $('form.my_form').submit(function(event) {
    event.preventDefault(); // Prevent the form from submitting via the browser
    var form = $(this);
    $.ajax({
      type: form.attr('method'),
      url: form.attr('action'),
      data: form.serialize()
    }).done(function(data) {
      // Optionally alert the user of success here...
    }).fail(function(data) {
      // Optionally alert the user of an error here...
    });
  });
});

ajax get form data

var form = // Select your form here;
var fmData = new FormData();
form.append('name',fmData);
$.ajax({
  url:'URL',
  type:'POST',
  data:fmData,
  success:function(){},
  error:(er){}
})

jquery form data

var fd = new FormData();    
fd.append( 'file', input.files[0] );

$.ajax({
  url: 'http://example.com/script.php',
  data: fd,
  processData: false,
  contentType: false,
  type: 'POST',
  success: function(data){
    alert(data);
  }
});

ajax submit form data

<form id="contactForm1" action="/your_url" method="post">
    <!-- Form input fields here (do not forget your name attributes). -->
</form>

<script type="text/javascript">
    var frm = $('#contactForm1');

    frm.submit(function (e) {

        e.preventDefault();

        $.ajax({
            type: frm.attr('method'),
            url: frm.attr('action'),
            data: frm.serialize(),
            success: function (data) {
                console.log('Submission was successful.');
                console.log(data);
            },
            error: function (data) {
                console.log('An error occurred.');
                console.log(data);
            },
        });
    });
</script>

Submit AJAX Forms with JQuery to database

// Database Structure 
CREATE TABLE `contacts` (
 `id` int(11) NOT NULL AUTO_INCREMENT,
 `name` text NOT NULL,
 `email` text NOT NULL,
 `reason` text NOT NULL,
 `message` text NOT NULL,
 PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=5 DEFAULT CHARSET=latin1

<?php
if(isset($_POST['submit_contact']))
{
 $name=$_POST['name'];
 $email=$_POST['email'];
 $reason=$_POST['reason'];
 $message=$_POST['message'];
	
 $host="localhost";
 $username="root";
 $password="";
 $databasename="sample";
 $connect=mysql_connect($host,$username,$password);
 $db=mysql_select_db($databasename);
 
 mysql_query("insert into contacts values('','$name','$email','$reason','$message')");
 echo "submitted";
 exit();
}
?>