Answers for "iterate through array of objects"

Javascript

javascript loop through array of objects es6

/* new options with IE6: loop through array of objects */

const people = [
  {id: 100, name: 'Vikash'},
  {id: 101, name: 'Sugam'},
  {id: 102, name: 'Ashish'}
];

// using for of
for (let persone of people) {
  console.log(persone.id + ': ' + persone.name);
}

// using forEach(...)
people.forEach(person => {
 console.log(persone.id + ': ' + persone.name);
});
// output of above two methods
// 100: Vikash
// 101: Sugam
// 102: Ashish


// forEach(...) with index
people.forEach((person, index) => {
 console.log(index + ': ' + persone.name);
});
// output of above code in console
// 0: Vikash
// 1: Sugam
// 2: Ashish

Posted by: Guest on May-04-2020

javascript loop through object array

var person={
 	first_name:"johnny",
  	last_name: "johnson",
	phone:"703-3424-1111"
};
for (var property in person) {
  	console.log(property,":",person[property]);
}

Posted by: Guest on July-22-2019

javascript loop through array of objects

let arr = [object0, object1, object2];

for (let elm of arr) {
  console.log(elm);
}

Posted by: Guest on June-01-2020

iterate over array of objects javascript

// Just loop through an array

const myArray = [{x:100}, {x:200}, {x:300}];

myArray.forEach((element, index, array) => {
    console.log(element.x); // 100, 200, 300
    console.log(index); // 0, 1, 2
    console.log(array); // same myArray object 3 times
});

Posted by: Guest on January-02-2021

Source

iterate over array of objects javascript

// Count the number of each category

const people = [
    {name: 'John', group: 'A'}, 
    {name: 'Andrew', group: 'C'}, 
    {name: 'Peter', group: 'A'}, 
    {name: 'James', group: 'B'}, 
    {name: 'Hanna', group: 'A'}, 
    {name: 'Adam', group: 'B'}];

const groupInfo = people.reduce((groups, person) => {
    const {A = 0, B = 0, C = 0} = groups;
    if (person.group === 'A') {
        return {...groups, A: A + 1};
    } else if (person.group === 'B') {
        return {...groups, B: B + 1};
    } else {
        return {...groups, C: C + 1};
    }
}, {});

console.log(groupInfo); // {A: 3, C: 1, B: 2}

Posted by: Guest on January-02-2021

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