Answers for "javascript iterate through array of objects"

Javascript

javascript loop through array of objects es6

/* new options with IE6: loop through array of objects */

const people = [
  {id: 100, name: 'Vikash'},
  {id: 101, name: 'Sugam'},
  {id: 102, name: 'Ashish'}
];

// using for of
for (let persone of people) {
  console.log(persone.id + ': ' + persone.name);
}

// using forEach(...)
people.forEach(person => {
 console.log(persone.id + ': ' + persone.name);
});
// output of above two methods
// 100: Vikash
// 101: Sugam
// 102: Ashish


// forEach(...) with index
people.forEach((person, index) => {
 console.log(index + ': ' + persone.name);
});
// output of above code in console
// 0: Vikash
// 1: Sugam
// 2: Ashish

Posted by: Guest on May-04-2020

javascript loop through object array

var person={
 	first_name:"johnny",
  	last_name: "johnson",
	phone:"703-3424-1111"
};
for (var property in person) {
  	console.log(property,":",person[property]);
}

Posted by: Guest on July-22-2019

javascript loop through array of objects

var people=[
  {first_name:"john",last_name:"doe"},
  {first_name:"mary",last_name:"beth"}
];
for (let i = 0; i < people.length; i++) { 
  console.log(people[i].first_name);
}

Posted by: Guest on June-17-2019

iterate through object array javascript

for (var key in array) {
    var obj = myArray[key];
    // ...
}

Posted by: Guest on March-12-2020

Source

iterate over array of objects javascript

// Sum up a particular property, and calculate its average

const myArray = [{x:100}, {x:200}, {x:300}];

const sum = myArray.map(element => element.x).reduce((a, b) => a + b, 0);
console.log(sum); // 600 = 0 + 100 + 200 + 300

const average = sum / myArray.length;
console.log(average); // 200

Posted by: Guest on January-02-2021

Source

iterate over array of objects javascript

// Sort an array

const people = [
  { name: "John", age: 21 },
  { name: "Peter", age: 31 },
  { name: "Andrew", age: 29 },
  { name: "Thomas", age: 25 }
];

let sortByAge = people.sort(function (p1, p2) {
  return p1.age - p2.age;
});

console.log(sortByAge);

Posted by: Guest on January-02-2021

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