how to filter an array of objects in javascript
let arr=[{id:1,title:'A', status:true}, {id:3,title:'B',status:true}, {id:2, title:'xys', status:true}];
//find where title=B
let x = arr.filter((a)=>{if(a.title=='B'){return a}});
console.log(x)//[{id:3,title:'B',status:true}]Filter Array of Objects with Array of Objects
const myArray = [{ userid: "100", projectid: "10", rowid: "0" }, { userid: "101", projectid: "11", rowid: "1"}, { userid: "102", projectid: "12", rowid: "2" }, { userid: "103", projectid: "13", rowid: "3" }, { userid: "101", projectid: "10", rowid: "4" }];
const myFilter = [{ userid: "101", projectid: "11" }, { userid: "102", projectid: "12" }, { userid: "103", projectid: "11"}];
const myArrayFiltered = myArray.filter((el) => {
return myFilter.some((f) => {
return f.userid === el.userid && f.projectid === el.projectid;
});
});
console.log(myArrayFiltered);javascript filter array of objects by array
var arr = [1,2,3,4],
brr = [2,4],
res = arr.filter(f => !brr.includes(f));
console.log(res);javascript filter array of objects
let people = [
{ name: "Steve", age: 27, country: "America" },
{ name: "Jacob", age: 24, country: "America" }
];
let filteredPeople = people.filter(function (currentElement) {
// the current value is an object, so you can check on its properties
return currentElement.country === "America" && currentElement.age < 25;
});
console.log(filteredPeople);
// [{ name: "Jacob", age: 24, country: "America" }]javascript array filter elements greater than
function isGreater(element, index, array) {
return (element >= 10);
}
let testElemets = [12, 5, 8, 130, 44].filter(isGreater);
console.log("Test Value : " + testElemets );filter out arrays js
let newArray = array.filter(function(item) {
return condition;
});Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
