filter using two array of objects
const arr1 = [{id:'1',name:'A'},{id:'2',name:'B'},{id:'3',name:'C'},{id:'4',name:'D'}];
const arr2 = [{id:'1',name:'A',state:'healthy'},{id:'3',name:'C',state:'healthy'}];
const filterByReference = (arr1, arr2) => {
let res = [];
res = arr1.filter(el => {
return !arr2.find(element => {
return element.id === el.id;
});
});
return res;
}
console.log(filterByReference(arr1, arr2));compare and filter two array of object
array1 = [{path: "hello"}, {path: "world"}];
array2 = [{path: "hello"}, {path: "hahah", text: "dsdsds"}];
//comparing array1 and array2 and returning unmatced from array1
Object.keys(array1)
.filter((val, index) => array1[index].path !== array2[index].path)
.map((val, index) => array1[index]);
// output
//[{"path": "world"}]comparing two array of objects in javascript returning differences
a = [{ value:"4a55eff3-1e0d-4a81-9105-3ddd7521d642", display:"Jamsheer"}, { value:"644838b3-604d-4899-8b78-09e4799f586f", display:"Muhammed"}, { value:"b6ee537a-375c-45bd-b9d4-4dd84a75041d", display:"Ravi"}, { value:"e97339e1-939d-47ab-974c-1b68c9cfb536", display:"Ajmal"}, { value:"a63a6f77-c637-454e-abf2-dfb9b543af6c", display:"Ryan"}]
b = [{ value:"4a55eff3-1e0d-4a81-9105-3ddd7521d642", display:"Jamsheer", $$hashKey:"008"}, { value:"644838b3-604d-4899-8b78-09e4799f586f", display:"Muhammed", $$hashKey:"009"}, { value:"b6ee537a-375c-45bd-b9d4-4dd84a75041d", display:"Ravi", $$hashKey:"00A"}, { value:"e97339e1-939d-47ab-974c-1b68c9cfb536", display:"Ajmal", $$hashKey:"00B"}]
function comparer(otherArray){
return function(current){
return otherArray.filter(function(other){
return other.value == current.value && other.display == current.display
}).length == 0;
}
}
var onlyInA = a.filter(comparer(b));
var onlyInB = b.filter(comparer(a));
result = onlyInA.concat(onlyInB);
console.log(result);Copyright © 2021 Codeinu
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