Answers for "javascript sort array of objects by key value"

3

array sort by key javascript

function sortByKey(array, key) {
  return array.sort((a, b) => {
    let x = a[key];
    let y = b[key];
    
    return ((x < y) ? -1 : ((x > y) ? 1 : 0));
  });
}
Posted by: Guest on April-10-2020
3

javascript sort object by key

function sortObjectByKeys(o) {
    return Object.keys(o).sort().reduce((r, k) => (r[k] = o[k], r), {});
}
var unsorted = {"c":"crane","b":"boy","a":"ant"};
var sorted=sortObjectByKeys(unsorted); //{a: "ant", b: "boy", c: "crane"}
Posted by: Guest on August-02-2019
7

javascript sort array of objects by key value

arr.sort((x, y) => x.distance - y.distance);
Posted by: Guest on March-15-2020
7

sort array of objects javascript by value

let orders = [
  { 
    order: 'order 1', date: '2020/04/01_11:09:05'
  },
  { 
    order: 'order 2', date: '2020/04/01_10:29:35'
  },
  { 
    order: 'order 3', date: '2020/04/01_10:28:44'
  }
];


console.log(orders);

orders.sort(function(a, b){
  let dateA = a.date.toLowerCase();
  let dateB = b.date.toLowerCase();
  if (dateA < dateB) 
  {
    return -1;
  }    
  else if (dateA > dateB)
  {
    return 1;
  }   
  return 0;
});

console.log(orders);
Posted by: Guest on April-01-2020
0

sort array of objects javascript by key value

myArray.sort(function(a, b) {
    return a.distance - b.distance;
});
Posted by: Guest on November-26-2020
0

sort() object values javascript

list.sort((a, b) => (a.color > b.color) ? 1 : (a.color === b.color) ? ((a.size > b.size) ? 1 : -1) : -1 )
Posted by: Guest on May-18-2020

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