Answers for "sort array of objects javascript by value"

24

sort array of object js

const books = [
  {id: 1, name: 'The Lord of the Rings'},
  {id: 2, name: 'A Tale of Two Cities'},
  {id: 3, name: 'Don Quixote'},
  {id: 4, name: 'The Hobbit'}
]

books.sort((a,b) => (a.name > b.name) ? 1 : ((b.name > a.name) ? -1 : 0));
Posted by: Guest on April-08-2021
19

javascript sort array with objects

var array = [
  {name: "John", age: 34},
  {name: "Peter", age: 54},
  {name: "Jake", age: 25}
];

array.sort(function(a, b) {
  return a.age - b.age;
}); // Sort youngest first
Posted by: Guest on May-20-2020
2

sort array with objects

const list = [
  { color: 'white', size: 'XXL' },
  { color: 'red', size: 'XL' },
  { color: 'black', size: 'M' }
]

var sortedArray = list.sort((a, b) => (a.color > b.color) ? 1 : -1)

// Result:
//sortedArray:
//{ color: 'black', size: 'M' }
//{ color: 'red', size: 'XL' }
//{ color: 'white', size: 'XXL' }
Posted by: Guest on June-06-2021
17

javascript sort array of objects

const books = [
  {id: 1, name: 'The Lord of the Rings'},
  {id: 2, name: 'A Tale of Two Cities'},
  {id: 3, name: 'Don Quixote'},
  {id: 4, name: 'The Hobbit'}
]

compareObjects(object1, object2, key) {
  const obj1 = object1[key].toUpperCase()
  const obj2 = object2[key].toUpperCase()

  if (obj1 < obj2) {
    return -1
  }
  if (obj1 > obj2) {
    return 1
  }
  return 0
}

books.sort((book1, book2) => {
  return compareObjects(book1, book2, 'name')
})

// Result:
// {id: 2, name: 'A Tale of Two Cities'}
// {id: 3, name: 'Don Quixote'}
// {id: 4, name: 'The Hobbit'}
// {id: 1, name: 'The Lord of the Rings'}
Posted by: Guest on February-25-2020
7

javascript sort array of objects by key value

arr.sort((x, y) => x.distance - y.distance);
Posted by: Guest on March-15-2020
7

sort array of objects javascript by value

let orders = [
  { 
    order: 'order 1', date: '2020/04/01_11:09:05'
  },
  { 
    order: 'order 2', date: '2020/04/01_10:29:35'
  },
  { 
    order: 'order 3', date: '2020/04/01_10:28:44'
  }
];


console.log(orders);

orders.sort(function(a, b){
  let dateA = a.date.toLowerCase();
  let dateB = b.date.toLowerCase();
  if (dateA < dateB) 
  {
    return -1;
  }    
  else if (dateA > dateB)
  {
    return 1;
  }   
  return 0;
});

console.log(orders);
Posted by: Guest on April-01-2020

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