Answers for "javascript sort array of objects by array"

26

sort array of object js

const books = [
  {id: 1, name: 'The Lord of the Rings'},
  {id: 2, name: 'A Tale of Two Cities'},
  {id: 3, name: 'Don Quixote'},
  {id: 4, name: 'The Hobbit'}
]

books.sort((a,b) => (a.name > b.name) ? 1 : ((b.name > a.name) ? -1 : 0));
Posted by: Guest on April-08-2021
19

javascript sort array with objects

var array = [
  {name: "John", age: 34},
  {name: "Peter", age: 54},
  {name: "Jake", age: 25}
];

array.sort(function(a, b) {
  return a.age - b.age;
}); // Sort youngest first
Posted by: Guest on May-20-2020
2

sort array with objects

const list = [
  { color: 'white', size: 'XXL' },
  { color: 'red', size: 'XL' },
  { color: 'black', size: 'M' }
]

var sortedArray = list.sort((a, b) => (a.color > b.color) ? 1 : -1)

// Result:
//sortedArray:
//{ color: 'black', size: 'M' }
//{ color: 'red', size: 'XL' }
//{ color: 'white', size: 'XXL' }
Posted by: Guest on June-06-2021
5

sort array of objects javascript

list.sort((a, b) => (a.color > b.color) ? 1 : -1)
Posted by: Guest on July-23-2020
13

sort array of objects javascript

var items = [
  { name: 'Edward', value: 21 },
  { name: 'Sharpe', value: 37 },
  { name: 'And', value: 45 },
  { name: 'The', value: -12 },
  { name: 'Magnetic', value: 13 },
  { name: 'Zeros', value: 37 }
];

// sort by value
items.sort(function (a, b) {
  return a.value - b.value;
});

// sort by name
items.sort(function(a, b) {
  var nameA = a.name.toUpperCase(); // ignore upper and lowercase
  var nameB = b.name.toUpperCase(); // ignore upper and lowercase
  if (nameA < nameB) {
    return -1;
  }
  if (nameA > nameB) {
    return 1;
  }

  // names must be equal
  return 0;
});
Posted by: Guest on May-30-2020
1

js sort array of object by key

/**
 * Function to sort alphabetically an array of objects by some specific key.
 * 
 * @param {String} property Key of the object to sort.
 */
function dynamicSort(property) {
    var sortOrder = 1;

    if(property[0] === "-") {
        sortOrder = -1;
        property = property.substr(1);
    }

    return function (a,b) {
        if(sortOrder == -1){
            return b[property].localeCompare(a[property]);
        }else{
            return a[property].localeCompare(b[property]);
        }        
    }
}
Posted by: Guest on September-10-2020

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