javascript sum of array
const sum = arr => arr.reduce((a, b) => a + b, 0);javascript sum of array
const sum = arr => arr.reduce((a, b) => a + b, 0);how to flatten array with reduce in javascript
let flattened = [[0, 1], [2, 3], [4, 5]].reduce(
function(accumulator, currentValue) {
return accumulator.concat(currentValue)
},
[]
)
// flattened is [0, 1, 2, 3, 4, 5]javascript reduce array of objects
var objs = [
{name: "Peter", age: 35},
{name: "John", age: 27},
{name: "Jake", age: 28}
];
objs.reduce(function(accumulator, currentValue) {
return accumulator + currentValue.age;
}, 0); // 35 + 27 + 28 = 90js reduce
Sum array elements:
let myArr = [1,2,3,-1,-34,0]
return myArr.reduce((a,b) => a + b,0)js reduce
let newArray = array.reduce( (acc, element, index, originalArray) => {
// return acc += element
}, initialValue)js reduce
// syntax: array.reduce(function, accumulator-initial-value)
let array = [3, 7, 2, 9, 5]
const result = array.reduce((accumulator, currentValue, currentIndex, arr) => {
// code
}, initialValue)
// accumulator = will store return value of the function
// currentValue = iterate through each array element
// currentIndex = index of currentValue
// arr = original array
// initialValue = set accumulator initial valueCopyright © 2021 Codeinu
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