sum of number using reduce
console.log(
[1, 2, 3, 4].reduce((a, b) => a + b, 0)
)
console.log(
[].reduce((a, b) => a + b, 0)
)sum of number using reduce
console.log(
[1, 2, 3, 4].reduce((a, b) => a + b, 0)
)
console.log(
[].reduce((a, b) => a + b, 0)
)javascript sum of array
const sum = arr => arr.reduce((a, b) => a + b, 0);javascript reduce sum
arrSum = function(arr){ return arr.reduce(function(a,b){ return a + b }, 0);}javascript reduce sum
let nums = [1, 2, 3];
nums.reduce((curr, next) => curr + next);.reduce mdn
arr.reduce(callback( accumulator, currentValue[, index[, array]] )[, initialValue])Copyright © 2021 Codeinu
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