js sum of array
[1, 2, 3, 4].reduce((a, b) => a + b, 0)
// Output: 10js sum of array
[1, 2, 3, 4].reduce((a, b) => a + b, 0)
// Output: 10sum of number using reduce
console.log(
[1, 2, 3, 4].reduce((a, b) => a + b, 0)
)
console.log(
[].reduce((a, b) => a + b, 0)
)javascript reduce sum
arrSum = function(arr){ return arr.reduce(function(a,b){ return a + b }, 0);}reduce javascript
//note idx and sourceArray are optional
const sum = array.reduce((accumulator, element[, idx[, sourceArray]]) => {
//arbitrary example of why idx might be needed
return accumulator + idx * 2 + element
}, 0);Copyright © 2021 Codeinu
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