Answers for "how to sort object value in javascript"

1

javascript sort object js

grossaryList = {
  'bread': 1,
  'apple': 6,
  'milk': 1, 
  'orange': 3,
  'broccoli': 2 
}

return Object
  .entries(grossaryList)
  .sort((a,b) => b[1]-a[1])

//=> [['apple', 6],['orange', 3],['broccoli', 2],['bread',1],['milk', 1]]
Posted by: Guest on April-27-2021
7

sort array of objects javascript by value

let orders = [
  { 
    order: 'order 1', date: '2020/04/01_11:09:05'
  },
  { 
    order: 'order 2', date: '2020/04/01_10:29:35'
  },
  { 
    order: 'order 3', date: '2020/04/01_10:28:44'
  }
];


console.log(orders);

orders.sort(function(a, b){
  let dateA = a.date.toLowerCase();
  let dateB = b.date.toLowerCase();
  if (dateA < dateB) 
  {
    return -1;
  }    
  else if (dateA > dateB)
  {
    return 1;
  }   
  return 0;
});

console.log(orders);
Posted by: Guest on April-01-2020
3

javascript sort object

var maxSpeed = {
    car: 300, 
    bike: 60, 
    motorbike: 200, 
    airplane: 1000,
    helicopter: 400, 
    rocket: 28800
};
var sortable = [];
for (var vehicle in maxSpeed) {
    sortable.push([vehicle, maxSpeed[vehicle]]);
}

sortable.sort(function(a, b) {
    return a[1] - b[1];
});

//[["bike", 60], ["motorbike", 200], ["car", 300],
//["helicopter", 400], ["airplane", 1000], ["rocket", 28800]]
Posted by: Guest on April-19-2020
0

sort() object values javascript

list.sort((a, b) => (a.color > b.color) ? 1 : (a.color === b.color) ? ((a.size > b.size) ? 1 : -1) : -1 )
Posted by: Guest on May-18-2020

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