Answers for "javascript sort list"

sorting array from highest to lowest javascript

// Sort an array of numbers 
let numbers = [5, 13, 1, 44, 32, 15, 500]

// Lowest to highest
let lowestToHighest = numbers.sort((a, b) => a - b);
//Output: [1,5,13,15,32,44,500]

//Highest to lowest
let highestToLowest = numbers.sort((a, b) => b-a);
//Output: [500,44,32,15,13,5,1]

sort array of objects javascript

list.sort((a, b) => (a.color > b.color) ? 1 : -1)

JS array sort

numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sort

javascript sort array smallest to largest

var numArray = [140000, 104, 99];
numArray.sort(function(a, b) {
  return a - b;
});

console.log(numArray);

javascript sort

var names = ["Peter", "Emma", "Jack", "Mia", "Eric"];
names.sort(); // ["Emma", "Eric", "Jack", "Mia", "Peter"]

var objs = [
  {name: "Peter", age: 35},
  {name: "Emma", age: 21},
  {name: "Jack", age: 53}
];

objs.sort(function(a, b) {
  return a.age - b.age;
}); // Sort by age (lowest first)

array sort js

arr = ['width', 'score', done', 'neither' ]
arr.sort() // results to ["done", "neither", "score", "width"]

arr.sort((a,b) => a.localeCompare(b)) 
// if a-b (based on their unicode values) produces a negative value, 
// a comes before b, the reverse if positive, and as is if zero

//When you sort an array with .sort(), it assumes that you are sorting strings
//. When sorting numbers, the default behavior will not sort them properly.
arr = [21, 7, 5.6, 102, 79]
arr.sort((a, b) => a - b) // results to [5.6, 7, 21, 79, 102]
// b - a will give you the reverse order of the sorted items 

//this explnation in not mine