Answers for "javascript sort list of objects"

15

sort by object property javascript

let list = [
  {
      name: "world"
  },
  {
      name: "hello",
  },
];

// This doesn't account for if names are the same between objects
let x = list.sort((a, b) => (a.name > b.name ? 1 : -1));

console.log(x);

/*
[
  {
      name: "hello",
  },
  {
      name: "world"
  },
];
*/
Posted by: Guest on August-23-2020
19

javascript sort array with objects

var array = [
  {name: "John", age: 34},
  {name: "Peter", age: 54},
  {name: "Jake", age: 25}
];

array.sort(function(a, b) {
  return a.age - b.age;
}); // Sort youngest first
Posted by: Guest on May-20-2020
1

sort array of objects javascript

const books = [
  {id: 1, name: 'The Lord of the Rings'},
  {id: 2, name: 'A Tale of Two Cities'},
  {id: 3, name: 'Don Quixote'},
  {id: 4, name: 'The Hobbit'}
]

books.sort((a, b) => a.name.localeCompare(b.name))
Posted by: Guest on September-16-2021
17

javascript sort array of objects

const books = [
  {id: 1, name: 'The Lord of the Rings'},
  {id: 2, name: 'A Tale of Two Cities'},
  {id: 3, name: 'Don Quixote'},
  {id: 4, name: 'The Hobbit'}
]

compareObjects(object1, object2, key) {
  const obj1 = object1[key].toUpperCase()
  const obj2 = object2[key].toUpperCase()

  if (obj1 < obj2) {
    return -1
  }
  if (obj1 > obj2) {
    return 1
  }
  return 0
}

books.sort((book1, book2) => {
  return compareObjects(book1, book2, 'name')
})

// Result:
// {id: 2, name: 'A Tale of Two Cities'}
// {id: 3, name: 'Don Quixote'}
// {id: 4, name: 'The Hobbit'}
// {id: 1, name: 'The Lord of the Rings'}
Posted by: Guest on February-25-2020
0

js sort array of objects

const drinks1 = [
	{name: 'lemonade', price: 90}, 
	{name: 'lime', price: 432}, 
	{name: 'peach', price: 23}
];

function sortDrinkByPrice(drinks) {
	return drinks.sort((a, b) => a.price - b.price);
}
Posted by: Guest on February-19-2021
11

javascript sort array of object by property

function sortByDate( a, b ) {
  if ( a.created_at < b.created_at ){
    return -1;
  }
  if ( a.created_at > b.created_at ){
    return 1;
  }
  return 0;
}

myDates.sort(sortByDate);//myDates is not sorted.
Posted by: Guest on February-11-2020

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