sort array of object js
const books = [ {id: 1, name: 'The Lord of the Rings'}, {id: 2, name: 'A Tale of Two Cities'}, {id: 3, name: 'Don Quixote'}, {id: 4, name: 'The Hobbit'} ] books.sort((a,b) => (a.name > b.name) ? 1 : ((b.name > a.name) ? -1 : 0));
sort by object property javascript
let list = [ { name: "world" }, { name: "hello", }, ]; // This doesn't account for if names are the same between objects let x = list.sort((a, b) => (a.name > b.name ? 1 : -1)); console.log(x); /* [ { name: "hello", }, { name: "world" }, ]; */
javascript sort array with objects
var array = [ {name: "John", age: 34}, {name: "Peter", age: 54}, {name: "Jake", age: 25} ]; array.sort(function(a, b) { return a.age - b.age; }); // Sort youngest first
sort array with objects
const list = [ { color: 'white', size: 'XXL' }, { color: 'red', size: 'XL' }, { color: 'black', size: 'M' } ] var sortedArray = list.sort((a, b) => (a.color > b.color) ? 1 : -1) // Result: //sortedArray: //{ color: 'black', size: 'M' } //{ color: 'red', size: 'XL' } //{ color: 'white', size: 'XXL' }
javascript sort array of objects
const books = [ {id: 1, name: 'The Lord of the Rings'}, {id: 2, name: 'A Tale of Two Cities'}, {id: 3, name: 'Don Quixote'}, {id: 4, name: 'The Hobbit'} ] compareObjects(object1, object2, key) { const obj1 = object1[key].toUpperCase() const obj2 = object2[key].toUpperCase() if (obj1 < obj2) { return -1 } if (obj1 > obj2) { return 1 } return 0 } books.sort((book1, book2) => { return compareObjects(book1, book2, 'name') }) // Result: // {id: 2, name: 'A Tale of Two Cities'} // {id: 3, name: 'Don Quixote'} // {id: 4, name: 'The Hobbit'} // {id: 1, name: 'The Lord of the Rings'}
javascript sort in array of objects
// Price Low To High array?.sort((a, b) => (a.price > b.price ? 1 : -1)) // Price High To Low array?.sort((a, b) => (a.price > b.price ? -1 : 1)) // Name A to Z array?.sort((a, b) => (a.name > b.name ? 1 : 1)) // Name Z to A array?.sort((a, b) => (a.name > b.name ? -1 : 1)) // Sort by date array.sort((a,b) => new Date(b.date) - new Date(a.date));
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