Answers for "javascript sort array of objects by key descending"

19

javascript sort array with objects

var array = [
  {name: "John", age: 34},
  {name: "Peter", age: 54},
  {name: "Jake", age: 25}
];

array.sort(function(a, b) {
  return a.age - b.age;
}); // Sort youngest first
Posted by: Guest on May-20-2020
7

sort array of objects javascript by value

let orders = [
  { 
    order: 'order 1', date: '2020/04/01_11:09:05'
  },
  { 
    order: 'order 2', date: '2020/04/01_10:29:35'
  },
  { 
    order: 'order 3', date: '2020/04/01_10:28:44'
  }
];


console.log(orders);

orders.sort(function(a, b){
  let dateA = a.date.toLowerCase();
  let dateB = b.date.toLowerCase();
  if (dateA < dateB) 
  {
    return -1;
  }    
  else if (dateA > dateB)
  {
    return 1;
  }   
  return 0;
});

console.log(orders);
Posted by: Guest on April-01-2020
0

sort array elements in descending order based on object key

homes.sort((a, b) => parseFloat(a.price) - parseFloat(b.price));
Posted by: Guest on March-22-2021
-1

javascript sort array of objects by key value ascending and descending order

function compareValues(key, order = 'asc') {
  return function innerSort(a, b) {
    if (!a.hasOwnProperty(key) || !b.hasOwnProperty(key)) {
      // property doesn't exist on either object
      return 0;
    }

    const varA = (typeof a[key] === 'string')
      ? a[key].toUpperCase() : a[key];
    const varB = (typeof b[key] === 'string')
      ? b[key].toUpperCase() : b[key];

    let comparison = 0;
    if (varA > varB) {
      comparison = 1;
    } else if (varA < varB) {
      comparison = -1;
    }
    return (
      (order === 'desc') ? (comparison * -1) : comparison
    );
  };
}
Posted by: Guest on June-28-2020
0

javascript sort object by value descending

javascript sort object by value descending


starWarsPeople.map(e=>{
    return e
  }).sort((a,b)=>{
    if (a.height-b.height>1) {return -1;}
    else if (a.height-b.height<1) {return 1;}
    else {return 0;}
  });
Posted by: Guest on May-17-2021

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