javascript sort array with objects
var array = [
{name: "John", age: 34},
{name: "Peter", age: 54},
{name: "Jake", age: 25}
];
array.sort(function(a, b) {
return a.age - b.age;
}); // Sort youngest firstjavascript sort array with objects
var array = [
{name: "John", age: 34},
{name: "Peter", age: 54},
{name: "Jake", age: 25}
];
array.sort(function(a, b) {
return a.age - b.age;
}); // Sort youngest firstsorting array from highest to lowest javascript
// Sort an array of numbers
let numbers = [5, 13, 1, 44, 32, 15, 500]
// Lowest to highest
let lowestToHighest = numbers.sort((a, b) => a - b);
//Output: [1,5,13,15,32,44,500]
//Highest to lowest
let highestToLowest = numbers.sort((a, b) => b-a);
//Output: [500,44,32,15,13,5,1]JS array sort
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortjavascript orderby
var items = [
{ name: 'Edward', value: 21 },
{ name: 'Sharpe', value: 37 },
{ name: 'And', value: 45 },
{ name: 'The', value: -12 },
{ name: 'Magnetic', value: 13 },
{ name: 'Zeros', value: 37 }
];
// sort by value
items.sort(function (a, b) {
return a.value - b.value;
});
// sort by name
items.sort(function(a, b) {
var nameA = a.name.toUpperCase(); // ignore upper and lowercase
var nameB = b.name.toUpperCase(); // ignore upper and lowercase
if (nameA < nameB) {
return -1;
}
if (nameA > nameB) {
return 1;
}
// names must be equal
return 0;
});sorting of arraray's number element in javascript
let numbers = [0, 1, 2, 3, 10, 20, 30];
numbers.sort((a, b) => a - b);
console.log(numbers);js index sorted
var test = ['b', 'c', 'd', 'a'];
var len = test.length;
var indices = new Array(len);
for (var i = 0; i < len; ++i) indices[i] = i;
indices.sort(function (a, b) { return test[a] < test[b] ? -1 : test[a] > test[b] ? 1 : 0; });
console.log(indices);Copyright © 2021 Codeinu
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