Answers for "array sort javascript"

6

javascript sort alphabetically

var items = ['réservé', 'premier', 'communiqué', 'café', 'adieu', 'éclair'];
items.sort(function (a, b) {
  return a.localeCompare(b); //using String.prototype.localCompare()
});

// items is ['adieu', 'café', 'communiqué', 'éclair', 'premier', 'réservé']
Posted by: Guest on May-01-2020
14

sorting array from highest to lowest javascript

// Sort an array of numbers 
let numbers = [5, 13, 1, 44, 32, 15, 500]

// Lowest to highest
let lowestToHighest = numbers.sort((a, b) => a - b);
//Output: [1,5,13,15,32,44,500]

//Highest to lowest
let highestToLowest = numbers.sort((a, b) => b-a);
//Output: [500,44,32,15,13,5,1]
Posted by: Guest on March-25-2020
20

JS array sort

numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sort
Posted by: Guest on May-08-2021
52

sort javascript array

var points = [40, 100, 1, 5, 25, 10];
points.sort((a,b) => a-b)
Posted by: Guest on June-07-2020
13

javascript orderby

var items = [
  { name: 'Edward', value: 21 },
  { name: 'Sharpe', value: 37 },
  { name: 'And', value: 45 },
  { name: 'The', value: -12 },
  { name: 'Magnetic', value: 13 },
  { name: 'Zeros', value: 37 }
];

// sort by value
items.sort(function (a, b) {
  return a.value - b.value;
});

// sort by name
items.sort(function(a, b) {
  var nameA = a.name.toUpperCase(); // ignore upper and lowercase
  var nameB = b.name.toUpperCase(); // ignore upper and lowercase
  if (nameA < nameB) {
    return -1;
  }
  if (nameA > nameB) {
    return 1;
  }

  // names must be equal
  return 0;
});
Posted by: Guest on May-30-2020
0

array sort javascript

const numbers = [3, 23, 12];

numbers.sort(function(a, b){return a - b}); // --> 3, 12, 23
Posted by: Guest on July-08-2021

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