Answers for "file ajax"

Javascript

-1

file ajax

function showUploadedItem (source) {
  var list = document.getElementById("image-list"),
      li   = document.createElement("li"),
      img  = document.createElement("img");
    img.src = source;
    li.appendChild(img);
  list.appendChild(li);
}

Posted by: Guest on November-24-2020

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