Answers for "ajax"

8

$.ajax javascript

$.ajax({
    url: 'https://example.com/your-page',
    success:function(data){
        //'data' is the value returned.
    },
    error:function(){
        alert('An error was encountered.');
    }
});
Posted by: Guest on May-30-2020
7

ajax

With Ajax, web applications can send and retrieve data from a server asynchronously without interfering with the display and behaviour of the existing page.
Posted by: Guest on August-21-2020
0

ajax

var xhr = new XMLHttpRequest;
var url = "/";

//POST request
xhr.open('POST', url); //Open the request.
xhr.setRequestHeader('Content-type', 'application/x-www-form-urlencoded'); //Set the necessary headers for the POST request.
xhr.onreadystatechange = () => {
  //Checking if the request has finished and if it was successfull  
  if (xhr.readyState == 4 && xhr.status == 200) {
        console.log(xhr.responseText); //Printing out the response. 
    	//You can also use xhr.responseURL or xhr.responseXML
    }
}
xhr.send("lorem=ipsum"); //This sends the request with the specified params. The params should be in format "key=value&key2=value2"
//You can also send a FormData object as the params.
Posted by: Guest on April-01-2021
0

ajax

AJAX - Asynchronous JavaScript And XML
Posted by: Guest on July-30-2021
1

ajax

var xhr = new XMLHttpRequest;
var url = "/?lorem=ipsum";

//GET request
xhr.open('GET', url); //Open the request with the specified url.
xhr.onreadystatechange = () => {
  //Checking if the request has finished and if it was successfull  
  if (xhr.readyState == 4 && xhr.status == 200) {
        console.log(xhr.responseText); //Printing out the response. 
    	//You can also use xhr.responseXML
    }
}
xhr.send(); //This sends the request to the server with the specified params.
Posted by: Guest on April-01-2021
0

ajax

$.ajax({
        method :'GET',
        url: baseUrl+'ajaxcontroller/LoadData_To_View',
        success:function(data){
        $('#item').html(data);
        alert(data);
        },
        complete: function(){
        $('#loadingImage2').hide();
        },
        error:function (xhr, ajaxOptions, thrownError){alert(thrownError);}
        });
Posted by: Guest on May-31-2021

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