Answers for "output specific values from json_decode php"

PHP
19

php json_decode

$personJSON = '{"name":"Johny Carson","title":"CTO"}';

$person = json_decode($personJSON);

echo $person->name; // Johny Carson
Posted by: Guest on July-01-2019
0

php decode json object

<?php

$json = '{"firstName":"Peter","lastName:":"Silva","age":23}';

$personInfo = json_decode(json);

echo $personInfo->age;

?>
Posted by: Guest on October-22-2020

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