Answers for "json_decode get values"

PHP
19

php json_decode

$personJSON = '{"name":"Johny Carson","title":"CTO"}';

$person = json_decode($personJSON);

echo $person->name; // Johny Carson
Posted by: Guest on July-01-2019
0

json_decode

$value = '{"Name" : "Tamer"}';

json_decode($value);
Posted by: Guest on April-29-2021

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