Answers for "php debug output"

console.log in php

/*
console.log in php
*/

<?php
	function consoleLog($message) {
		echo '<script type="text/javascript">' .
          'console.log(' . $message . ');</script>';
	}

	consoleLog('Hello, greppers!');
?>

console_log in php

<?php
function console_log($output, $with_script_tags = true) {
    $js_code = 'console.log(' . json_encode($output, JSON_HEX_TAG) . 
');';
    if ($with_script_tags) {
        $js_code = '<script>' . $js_code . '</script>';
    }
    echo $js_code;
}