implicit if python
x = a if b else 0
implicit if python
x = a if b else 0
python inline conditional
x = 10 if False else 0
python inline if
Python does not have a trailing if statement.
There are two kinds of if in Python:
1. if statement:
if condition: statement
if condition:
block
2. if expression (introduced in Python 2.5)
expression_if_true if condition else expression_if_false
And note, that both print a and b = a are statements. Only the a part is an expression. So if you write
print a if b else 0
it means
print (a if b else 0)
and similarly when you write
x = a if b else 0
it means
x = (a if b else 0)
Now what would it print/assign if there was no else clause? The print/assignment is still there.
And note, that if you don't want it to be there, you can always write the regular if statement on a single line, though it's less readable and there is really no reason to avoid the two-line variant.
python oneline if
# Cigar Party problem in https://codingbat.com/prob/p195669
def cigar_party(cigars, is_weekend):
result = False
result = True if (is_weekend and cigars >= 40) or (cigars >= 40 and cigars <= 60) else False
return result
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