apply lambda with if
df['new column name'] = df['column name'].apply(lambda x: 'value if condition is met' if x condition else 'value if condition is not met')apply lambda with if
df['new column name'] = df['column name'].apply(lambda x: 'value if condition is met' if x condition else 'value if condition is not met')how to use if else in lambda python
lambda <arguments> : <Return Value if condition is True> if <condition> else <Return Value if condition is False>
lambda x : True if (x > 10 and x < 20) else Falselambda condition python
f = lambda parameter : exp1 if cond else exp2
# example
f = lambda x: "even" if x%2==0 else "odd"Copyright © 2021 Codeinu
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