Answers for "armstrong number python"

1

Take n as input and check which ones are Armstrong number using a function in the range 1 to n in python

num = 370
# Changed num variable to string, 
# and calculated the length (number of digits)
order = len(str(num))
# initialize sum
sum = 0
# find the sum of the cube of each digit
temp = num
while temp > 0:
   digit = temp % 10
   sum += digit ** order
   temp //= 10
# display the result
if num == sum:
   print(num,"is an Armstrong number")
else:
   print(num,"is not an Armstrong number")
#Output-- 370 is an Armstrong number
Posted by: Guest on August-18-2020
2

armstrong number python

a = 1634
aa = str(a)
lenn = len(aa)
count = 0
for i in range(lenn):
    count +=  int(aa[i]) ** 4
if count == a :
    print("Yes")
else:
    print('No')
Posted by: Guest on August-30-2021
1

armstrong number in python

# Program to check Armstrong numbers in a certain interval

lower = 100
upper = 2000

for num in range(lower, upper + 1):

   # order of number
   order = len(str(num))
    
   # initialize sum
   sum = 0

   temp = num
   while temp > 0:
       digit = temp % 10
       sum += digit ** order
       temp //= 10

   if num == sum:
       print(num)
Posted by: Guest on January-14-2021

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