Answers for "armstrong python"

Take n as input and check which ones are Armstrong number using a function in the range 1 to n in python

num = 370
# Changed num variable to string, 
# and calculated the length (number of digits)
order = len(str(num))
# initialize sum
sum = 0
# find the sum of the cube of each digit
temp = num
while temp > 0:
   digit = temp % 10
   sum += digit ** order
   temp //= 10
# display the result
if num == sum:
   print(num,"is an Armstrong number")
else:
   print(num,"is not an Armstrong number")
#Output-- 370 is an Armstrong number

armstrong number python

a = 1634
aa = str(a)
lenn = len(aa)
count = 0
for i in range(lenn):
    count +=  int(aa[i]) ** 4
if count == a :
    print("Yes")
else:
    print('No')