Answers for "sort a dictionary"

how can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

python sort dict by key

A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A)}

output:
{-1: 4, 1: 2, 4: -20}

sort a dictionary

from operator import itemgetter
new_dict = sorted(data.items(), key=itemgetter(1))

how to sort a dictionary py

orders = {
	'cappuccino': 54,
	'latte': 56,
	'espresso': 72,
	'americano': 48,
	'cortado': 41
}

sort_orders = sorted(orders.items(), key=lambda x: x[1], reverse=True)

for i in sort_orders:
	print(i[0], i[1])

sort dictionary by key

dictionary_items = a_dictionary.items()
sorted_items = sorted(dictionary_items)

dict sort

[(k,di[k]) for k in sorted(di.keys())]