Answers for "how to check if a number is armstrong in python"

how to check if a number is armstrong in python

num = 1634

# Changed num variable to string, 
# and calculated the length (number of digits)
order = len(str(num))

# initialize sum
sum = 0

# find the sum of the cube of each digit
temp = num
while temp > 0:
   digit = temp % 10
   sum += digit ** order
   temp //= 10

# display the result
if num == sum:
   print(num,"is an Armstrong number")
else:
   print(num,"is not an Armstrong number")

how to check if a number is armstrong in python

# Python program to check if the number is an Armstrong number or not

# take input from the user
num = int(input("Enter a number: "))

# initialize sum
sum = 0

# find the sum of the cube of each digit
temp = num
while temp > 0:
   digit = temp % 10
   sum += digit ** 3
   temp //= 10

# display the result
if num == sum:
   print(num,"is an Armstrong number")
else:
   print(num,"is not an Armstrong number")

armstrong number in python

# Program to check Armstrong numbers in a certain interval

lower = 100
upper = 2000

for num in range(lower, upper + 1):

   # order of number
   order = len(str(num))
    
   # initialize sum
   sum = 0

   temp = num
   while temp > 0:
       digit = temp % 10
       sum += digit ** order
       temp //= 10

   if num == sum:
       print(num)