Answers for "python *args"

28

args kwargs python

>>> def argsKwargs(*args, **kwargs):
...     print(args)
...     print(kwargs)
... 
>>> argsKwargs('1', 1, 'slgotting.com', upvote='yes', is_true=True, test=1, sufficient_example=True)
('1', 1, 'slgotting.com')
{'upvote': 'yes', 'is_true': True, 'test': 1, 'sufficient_example': True}
Posted by: Guest on July-16-2020
3

variable number of arguments to python class

def multiply(*args):
    z = 1
    for num in args:
        z *= num
    print(z)

multiply(4, 5)
multiply(10, 9)
multiply(2, 3, 4)
multiply(3, 5, 10, 6)
Posted by: Guest on July-18-2020
1

python *args

# concatenate_keys.py
def concatenate(**kwargs):
    result = ""
    # Iterating over the keys of the Python kwargs dictionary
    for arg in kwargs:
        result += arg
    return result

print(concatenate(a="Real", b="Python", c="Is", d="Great", e="!"))
Posted by: Guest on November-27-2020
0

*args python javascript equivalent

//spread operator
a = [1, 2, 3]

function printArgs(args) {
	console.log(...args)
}

printArgs(a)
//=> 1 2 3
Posted by: Guest on April-07-2020
0

args in python

def func(*args):
    x = []          # emplty list
    for i in args:
        i = i * 2
        x.append(i)  
        y = tuple(x) # converting back list into tuple
    return y
        
tpl = (2,3,4,5)        
print(func(*tpl))
Posted by: Guest on June-24-2021
0

args in python

# if args is not passed it return message
# "Hey you didn't pass the arguements"

def ech(num,*args):  
    if args:
        a = []
        for i in args:
            a.append(i**num)
        return a                 # return should be outside loop
    else:
        return "Hey you didn't pass the arguements"     # return should be outside loop
    
print(ech(3))
Posted by: Guest on June-24-2021

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