python get command line arguments
import sys
print("This is the name of the script:", sys.argv[0])
print("Number of arguments:", len(sys.argv))
print("The arguments are:" , str(sys.argv))
#Example output
#This is the name of the script: sysargv.py
#Number of arguments in: 3
#The arguments are: ['sysargv.py', 'arg1', 'arg2']pass argument to a py file
import sys
def hello(a,b):
print "hello and that's your sum:", a + b
if __name__ == "__main__":
a = int(sys.argv[1])
b = int(sys.argv[2])
hello(a, b)
# If you type : py main.py 1 5
# It should give you "hello and that's your sum:6"python command line argument list try
1 # argv.py
2 import sys
3
4 print(f"Name of the script : {sys.argv[0]=}")
5 print(f"Arguments of the script : {sys.argv[1:]=}")python argument command line
#!/usr/bin/python
import sys
print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)cli args python
import argparse
parser = argparse.ArgumentParser(description='Process some integers.')
parser.add_argument('integers', metavar='N', type=int, nargs='+',
help='an integer for the accumulator')
parser.add_argument('--sum', dest='accumulate', action='store_const',
const=sum, default=max,
help='sum the integers (default: find the max)')
args = parser.parse_args()
print(args.accumulate(args.integers))Copyright © 2021 Codeinu
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