Answers for "python dict remove duplicates where items are not the same"

8

removing duplicates from dictionary python

student_data = {'id1': 
   {'name': ['Sara'], 
    'class': ['V'], 
    'subject_integration': ['english, math, science']
   },
 'id2': 
  {'name': ['David'], 
    'class': ['V'], 
    'subject_integration': ['english, math, science']
   },
 'id3': 
    {'name': ['Sara'], 
    'class': ['V'], 
    'subject_integration': ['english, math, science']
   },
 'id4': 
   {'name': ['Surya'], 
    'class': ['V'], 
    'subject_integration': ['english, math, science']
   },
}

result = {}

for key,value in student_data.items():
    if value not in result.values():
        result[key] = value

print(result)
Posted by: Guest on October-22-2020
0

python dict remove duplicates where items are not the same

import itertools
mylist = [{'x':2020 , 'y':20},{'x':2020 , 'y':30},{'x':2021 , 'y':10},{'x':2021 , 'y':5}]
mylist1=[]
for key, group in itertools.groupby(mylist,lambda x:x["x"]):
    max_y=0
    for thing in group:
        max_y=max(max_y,thing["y"])
    mylist1.append({"x":key,"y":max_y})
print(mylist1)
Posted by: Guest on September-16-2021
-1

python remove duplicates from list of dict

# set the dict to a tuple for hashability, then use {} for set literal and retrn each item to dict. 
[dict(t) for t in {tuple(d.items()) for d in l}]
# using two maps()
list(map(lambda t: dict(t), set(list(map(lambda d: tuple(d.items()), l)))))
Posted by: Guest on March-27-2021

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