pattern in python
rows = 6 #Pattern(1,121,12321,1234321,123454321)
for i in range(1, rows + 1):
for j in range(1, i - 1):
print(j, end=" ")
for j in range(i - 1, 0, -1):
print(j, end=" ")
print()pattern in python
rows = 6 #Pattern(1,121,12321,1234321,123454321)
for i in range(1, rows + 1):
for j in range(1, i - 1):
print(j, end=" ")
for j in range(i - 1, 0, -1):
print(j, end=" ")
print()python re compile
import re
# Compile a regular expression pattern into a regular expression object, which can be used for matching using its match(), search() and other methods, described below.
prog = re.compile(pattern)
result = prog.match(string)
# is equivalent to
result = re.match(pattern, string)re.match() python
import re
pattern = '^a...s$'
test_string = 'abyss'
result = re.match(pattern, test_string)
if result:
print("Search successful.")
else:
print("Search unsuccessful.")python re
if pattern := re.search("[iI] am (.*)", "I am tired"):
print(f"Hi {pattern.group(1)}, I'm dad!")* pattern by python
def pattern(n):
for i in range(0,n):
for j in range(0, i+1):
print("* " , end="")
print("\r") pattern(5python pattern
python
import re
v = "aeiou"
c = "qwrtypsdfghjklzxcvbnm"
print(*re.findall("(?=[%s]([%s]{2,})[%s])"%(c,v,c),input(), re.I) or [-1], sep="\n")Copyright © 2021 Codeinu
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