Answers for "applymap(lambda x: x.encode('unicode_escape'). decode('utf-8') if isinstance(x, str) else x)"

0

applymap(lambda x: x.encode('unicode_escape'). decode('utf-8') if isinstance(x, str) else x)

dataframe = dataframe.applymap(lambda x: x.encode('unicode_escape').
                 decode('utf-8') if isinstance(x, str) else x)
Posted by: Guest on November-29-2020

Python Answers by Framework

Browse Popular Code Answers by Language