get index of list python
list.index(element)get index of list python
list.index(element)python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1python string indexing
str = 'codegrepper'
# str[start:end:step]
#by default: start = 0, end = len(str), step = 1
print(str[:]) #codegrepper
print(str[::]) #codegrepper
print(str[5:]) #repper
print(str[:8]) #codegrep
print(str[::2]) #cdgepr
print(str[2:8]) #degrep
print(str[2:8:2]) #dge
#step < 0 : reverse
print(str[::-1]) #reppergedoc
print(str[::-3]) #rpgo
# str[start:end:-1] means start from the end, go backward and stop at start
print(str[8:3:-1]) #ppergpython index of element in list
# alphabets list
alphabets = ['a', 'e', 'i', 'o', 'g', 'l', 'i', 'u']
# index of 'i' in alphabets
index = alphabets.index('i') # 2
print('The index of i:', index)
# 'i' after the 4th index is searched
index = alphabets.index('i', 4) # 6
print('The index of i:', index)
# 'i' between 3rd and 5th index is searched
index = alphabets.index('i', 3, 5) # Error!
print('The index of i:', index)python index method
my_string = "Hello World!"
my_string.index("l") # outputs 2
# this method only outputs the index of the first "l" value in the string/listindex of python
# Python is a 0-based indexing language, meanign all indices start from 0
list1 = ["Python", "Is", "A", "0", "Based", "Indexing", "language"]
print(list1[0]) # Prints Python.... the element on index 0, 1 in human countingCopyright © 2021 Codeinu
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