Answers for "python index of string"

13

python string indexing

str = 'codegrepper'
# str[start:end:step]
#by default: start = 0, end = len(str), step = 1
print(str[:]) 		#codegrepper
print(str[::]) 		#codegrepper
print(str[5:]) 		#repper
print(str[:8]) 		#codegrep
print(str[::2]) 	#cdgepr
print(str[2:8]) 	#degrep
print(str[2:8:2]) 	#dge
#step < 0 : reverse
print(str[::-1]) 	#reppergedoc
print(str[::-3]) 	#rpgo
# str[start:end:-1]	means start from the end, go backward and stop at start
print(str[8:3:-1]) 	#pperg
Posted by: Guest on September-12-2020
4

python string indexof

s = "mouse"
animal_letter = s.find('s')
print animal_letter
Posted by: Guest on May-18-2020
14

python index of string

string = "Hello World"
string_slice = string[1:10] # "ello Worl" (index 1 up to 10)
string_last_chars = string[-5:] # "World" (5th index from last to the end)
H = string[0] # "H"
Posted by: Guest on March-15-2020
0

python string index of

sentence = 'Python programming is fun.'

result = sentence.index('is fun')
print("Substring 'is fun':", result)

result = sentence.index('Java')
print("Substring 'Java':", result)
Posted by: Guest on May-30-2020
0

python string index

# Start from zero and the return value is exact index of first letter
Posted by: Guest on December-22-2020
0

how to find the indexes of a substring in a string in python

import re
# matches_position_start will be a list of starting index positions
matches_start = re.finditer(word.lower(), string.lower())
matches_position_start = [match.start() for match in matches_start]

# matches_position_end will be a list of ending index positions
matches_end = re.finditer(word.lower(), string.lower())
matches_position_end = [match.end() for match in matches_end]
Posted by: Guest on November-19-2020

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