python get index of substring in liast
index = [idx for idx, s in enumerate(l) if 'tiger' in s][0]python get index of substring in liast
index = [idx for idx, s in enumerate(l) if 'tiger' in s][0]python string indexing
str = 'codegrepper'
# str[start:end:step]
#by default: start = 0, end = len(str), step = 1
print(str[:]) #codegrepper
print(str[::]) #codegrepper
print(str[5:]) #repper
print(str[:8]) #codegrep
print(str[::2]) #cdgepr
print(str[2:8]) #degrep
print(str[2:8:2]) #dge
#step < 0 : reverse
print(str[::-1]) #reppergedoc
print(str[::-3]) #rpgo
# str[start:end:-1] means start from the end, go backward and stop at start
print(str[8:3:-1]) #ppergfind the index of a character in a string python
my_var = 'mummy'. #Find the position of 'm'
#Using find - find returns the index for the first instance from the left.
my_var.find('m')
# Output: 0
#Using rfind - rfind returns the index for the first instance from the right.
my_var.rfind('m')
# Output: 3
# With find() and rfind(), when substring is not found, it returns -1.
#NB: You can use index() and rindex(). In this case, when the substring is not
# found, it raises an exception.python get index of substring in liast
def index_containing_substring(the_list, substring):
for i, s in enumerate(the_list):
if substring in s:
return i
return -1python string index of
sentence = 'Python programming is fun.'
result = sentence.index('is fun')
print("Substring 'is fun':", result)
result = sentence.index('Java')
print("Substring 'Java':", result)Copyright © 2021 Codeinu
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