insertion sort python
def insertionSort(alist):
for i in range(1,len(alist)):
#element to be compared
current = alist[i]
#comparing the current element with the sorted portion and swapping
while i>0 and alist[i-1]>current:
alist[i] = alist[i-1]
i = i-1
alist[i] = current
#print(alist)
return alist
print(insertionSort([5,2,1,9,0,4,6]))insertion sort in python
def insertion(s):
for i in range(0,len(s)-1):
if s[i]>s[i+1]:
s[i],s[i+1]=s[i+1],s[i]
for j in range(i,0,-1):
if s[j]<s[j-1]:
s[j],s[j-1]=s[j-1],s[j]
print(s)
insertion([5,2,1,9,0,4,6])insertion sort python
#Insertion sort
ar = [34, 42, 22, 54, 19, 5]
for i in range(1, len(ar)):
while ar[i-1] > ar[i] and i > 0:
ar[i-1], ar[i] = ar[i], ar[i-1]
i -= 1
print(ar)insertion sort
// Por ter uma complexidade alta,
// não é recomendado para um conjunto de dados muito grande.
// Complexidade: O(n²) / O(n**2) / O(n^2)
// @see https://www.youtube.com/watch?v=TZRWRjq2CAg
// @see https://www.cs.usfca.edu/~galles/visualization/ComparisonSort.html
function insertionSort(vetor) {
let current;
for (let i = 1; i < vetor.length; i += 1) {
let j = i - 1;
current = vetor[i];
while (j >= 0 && current < vetor[j]) {
vetor[j + 1] = vetor[j];
j--;
}
vetor[j + 1] = current;
}
return vetor;
}
insertionSort([1, 2, 5, 8, 3, 4])insertion sort in python
def tri_insert(tab):
for i in range(1, len(tab)):
k = tab[i]
j = i-1
while j >= 0 and k < tab[j] :
tab[j + 1] = tab[j]
j -= 1
tab[j + 1] = k
return tabCopyright © 2021 Codeinu
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