python itertools repeat()
# How to use it:
# repeat(var, amount)
# repeat() is basically like range() but it gives an extra arg for a var
from itertools import repeat
for x in repeat("Spam? Or Eggs?", 3):
print(x)
> "Spam? Or Eggs?"
> "Spam? Or Eggs?"
> "Spam? Or Eggs?"python product
#from itertools import product
def product(*args, **kwds):
# product('ABCD', 'xy') --> Ax Ay Bx By Cx Cy Dx Dy
# product(range(2), repeat=3) --> 000 001 010 011 100 101 110 111
pools = map(tuple, args) * kwds.get('repeat', 1)
result = [[]]
for pool in pools:
result = [x+[y] for x in result for y in pool]
for prod in result:
yield tuple(prod)itertools
from itertools import combinations
from itertools import permutationsitertools
from itertools import combinations_with_replacement
s, k = input().split()
for c in combinations_with_replacement(sorted(s), int(k)):
print("".join(c))intertools combinations implementation
def combinations(iterable, r):
# combinations('ABCD', 2) --> AB AC AD BC BD CD
# combinations(range(4), 3) --> 012 013 023 123
pool = tuple(iterable)
n = len(pool)
if r > n:
return
indices = range(r)
yield tuple(pool[i] for i in indices)
while True:
for i in reversed(range(r)):
if indices[i] != i + n - r:
break
else:
return
indices[i] += 1
for j in range(i+1, r):
indices[j] = indices[j-1] + 1
yield tuple(pool[i] for i in indices)itertools python
import itertools
set = "abcde"
for L in range(0, len(set) + 1)
for subset in itertools.combinations(letters, L): #all combinations in subset
list_comb.append(subset)Copyright © 2021 Codeinu
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