fibonacci sequence python
# WARNING: this program assumes the
# fibonacci sequence starts at 1
def fib(num):
"""return the number at index `num` in the fibonacci sequence"""
if num <= 2:
return 1
return fib(num - 1) + fib(num - 2)
# method 2: use `for` loop
def fib2(num):
a, b = 1, 1
for _ in range(num - 1):
a, b = b, a + b
return a
print(fib(6)) # 8
print(fib2(6)) # same result, but much fasterfibonacci python
# Implement the fibonacci sequence
# (0, 1, 1, 2, 3, 5, 8, 13, etc...)
def fib(n):
if n== 0 or n== 1:
return n
return fib (n- 1) + fib (n- 2)fibonacci sequence python
# WARNING: this program assumes the
# fibonacci sequence starts at 1
def fib(num):
"""return the number at index num in the fibonacci sequence"""
if num <= 2:
return 1
return fib(num - 1) + fib(num - 2)
print(fib(6)) # 8fibonacci sequence python
def fib(n):
a = 0
b = 1
print(a)
print(b)
for i in range(2, n):
print(a+b)
a, b = b, a + b
fib(7) #first seven nubers of Fibonacci sequencefibonacci sequence python
# This program also assumes the fibonacci sequence starts at 1
# This code will print as many digits as the user wishes
# Instead of printing a specific number in the sequence
def fibonacci(digits):
digit1, digit2 = 1, 1
amount_of_digits = 0
print(str(digit1) + ", " + str(digit2) + ', ', end='')
while amount_of_digits != digits:
digit1, digit2 = digit2, digit1 + digit2
print(str(digit2) + ", ", end='') # we want to print on the same line
amount_of_digits = amount_of_digits + 1
if amount_of_digits == digits:
print('\n')
print('Loop done.')
break
fibonacci(10) # this will print the first 10 digits in the sequenceCopyright © 2021 Codeinu
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