fibonacci sequence python
# WARNING: this program assumes the
# fibonacci sequence starts at 1
def fib(num):
"""return the number at index `num` in the fibonacci sequence"""
if num <= 2:
return 1
return fib(num - 1) + fib(num - 2)
# method 2: use `for` loop
def fib2(num):
a, b = 1, 1
for _ in range(num - 1):
a, b = b, a + b
return a
print(fib(6)) # 8
print(fib2(6)) # same result, but much fasterpython fibonacci
def Fibonacci( pos ):
#check for the terminating condition
if pos <= 1 :
#Return the value for position 1, here it is 0
return 0
if pos == 2:
#return the value for position 2, here it is 1
return 1
#perform some operation with the arguments
#Calculate the (n-1)th number by calling the function itself
n_1 = Fibonacci( pos-1 )
#calculation the (n-2)th number by calling the function itself again
n_2 = Fibonacci( pos-2 )
#calculate the fibo number
n = n_1 + n_2
#return the fibo number
return n
#Here we asking the function to calculate 5th Fibonacci
nth_fibo = Fibonacci( 5 )
print (nth_fibo)code fibonacci python
# Program to display the Fibonacci sequence forever
def fibonacci(i,j):
print(i;fibonacci(j,i+j))
fibonacci(1,1)fibonacci sequence python
# This program also assumes the fibonacci sequence starts at 1
# This code will print as many digits as the user wishes
# Instead of printing a specific number in the sequence
def fibonacci(digits):
digit1, digit2 = 1, 1
amount_of_digits = 0
print(str(digit1) + ", " + str(digit2) + ', ', end='')
while amount_of_digits != digits:
digit1, digit2 = digit2, digit1 + digit2
print(str(digit2) + ", ", end='') # we want to print on the same line
amount_of_digits = amount_of_digits + 1
if amount_of_digits == digits:
print('\n')
print('Loop done.')
break
fibonacci(10) # this will print the first 10 digits in the sequenceCopyright © 2021 Codeinu
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