pandas select column by index
# A B C
# 0 1 3 5
# 1 2 4 6
column_B = a_dataframe.iloc[:, 1]
print(column_B)
# OUTPUT
# 0 3
# 1 4pandas select column by index
# A B C
# 0 1 3 5
# 1 2 4 6
column_B = a_dataframe.iloc[:, 1]
print(column_B)
# OUTPUT
# 0 3
# 1 4pandas dataframe show one row
df.iloc[0,:]isolate row based on index pandas
dfObj.iloc[: , [0, 2]]pandas column by index
DataFrame.iloc[:, n]select rows from dataframe pandas
from pandas import DataFrame
boxes = {'Color': ['Green','Green','Green','Blue','Blue','Red','Red','Red'],
'Shape': ['Rectangle','Rectangle','Square','Rectangle','Square','Square','Square','Rectangle'],
'Price': [10,15,5,5,10,15,15,5]
}
df = DataFrame(boxes, columns= ['Color','Shape','Price'])
select_color = df.loc[df['Color'] == 'Green']
print (select_color)select columns pandas
df1 = df.iloc[:,0:2] # Remember that Python does not slice inclusive of the ending index.Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
