python merge dictionaries
# Python >= 3.5:
def merge_dictionaries(a, b):
return {**a, **b}
# else:
def merge_dictionaries(a, b):
c = a.copy() # make a copy of a
c.update(b) # modify keys and values of a with the b ones
return c
a = { 'x': 1, 'y': 2}
b = { 'y': 3, 'z': 4}
print(merge_dictionaries(a, b)) # {'y': 3, 'x': 1, 'z': 4}merge dicts python
z = x | y # NOTE: 3.9+ ONLY
z = {**x, **y} # NOTE: 3.5+ ONLYconvert two lists to a single dictionary python
#initialize lists
key_list = ['red', 'green', 'blue']
value_list = [1, 2, 3]
#convert lists
my_dict = {}
for key in key_list:
for value in value_list:
my_dict[key] = value
value_list.remove(value)
break
print(my_dict)merged all dictionaries in a list python
>>> result = {}
>>> for d in L:
... result.update(d)
...
>>> result
{'a':1,'c':1,'b':2,'d':2}merge a list of dictionaries python
>>> from collections import ChainMap
>>> a = [{'a':1},{'b':2},{'c':1},{'d':2}]
>>> dict(ChainMap(*a))
{'b': 2, 'c': 1, 'a': 1, 'd': 2}merge two list of dictionaries python with string
import pandas as pd
l1 = [{'id': 9, 'av': 4}, {'id': 10, 'av': 0}, {'id': 8, 'av': 0}]
l2 = [{'id': 9, 'nv': 45}, {'id': 10, 'nv': 0}, {'id': 8, 'nv': 30}]
df1 = pd.DataFrame(l1).set_index('id')
df2 = pd.DataFrame(l2).set_index('id')
df = df1.merge(df2, left_index=True, right_index=True)
df.T.to_dict()
# {9: {'av': 4, 'nv': 45}, 10: {'av': 0, 'nv': 0}, 8: {'av': 0, 'nv': 30}}Copyright © 2021 Codeinu
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